Question

an element belonging to 14th group of the periodic table has two allotropes 'p' and 'Q' . p is very hand and is non conductor of electricity while Q is opposite. (a) identify the element (b) name p and q (c) how do these two forms differ in their structure (d) name one other allotrope of the element except from p and q​

Answer 1

(a) Element - Carbon

(b) P - Diamond Q- Graphite

(c) Both are differ by number of covalent bonds around the carbon atom.

(d) Fulleren, Graphene

Step by step explanation:

(a)

The element is belongs to the 14th group and it has allotropes and element is carbon.

(b)

Two or more forms of element and having different physical properties called allotropes.

Most important allotropic forms of carbon are Diamond and Graphite.

Therefore, P and Q are Diamond and Graphite respectively.

(c)

Diamond is very stable allotropic form of carbon and it have $\bold{sp^{3}}$ hybridized carbon atom. Each carbon surrounded by four covalent bonds.

Graphite have $\bold{sp^{2}}$ hybridized carbon. Each carbon surrounded by three covalent bonds.

(d)

BC8,Fullerene,nanotube andgraphene are other allotropes of carbon .

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Answer 2

(a) carbon

(b) p -- diamond, q -- graphite

(c) by nunumber of covalent bonds around

(d) fulleren, graphene