an element belonging to 14th group of the periodic table has two allotropes 'p' and 'Q' . p is very hand and is non conductor of electricity while Q is opposite. (a) identify the element (b) name p and q (c) how do these two forms differ in their structure (d) name one other allotrope of the element except from p and q.
Answers
Answer:
carbon
Explanation:
a) carbon
b) p is diamond and q is graphite
c) graphite has the carbon atoms arranged in the form of sheets whereas the diamond has 3d arrangement of carbon atoms.
d) Buckminster fullerene
(a) The element is identified as carbon.
(b) 'P' is diamond.
(c) 'Q' is graphite.
Explanation:
Since, the given element belongs to group 14 so it will have 4 valence electrons. As it is known that an element which exists in one or more number of physical states is called an allotrope.
Carbon element being a non-metal is non-conducting in nature. So, the allotropes of carbon are graphite and diamond. Where graphite is conducting in nature and diamond is non-conducting in nature.
Read more about conductors:
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Read more about non-conductors:
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