An element crystallizes in a BCC lattice with cell edge of 500 picometre the density of element is 7.5 gram per centimetre cube how many atoms are present in 300 gram of the element
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d = 7.5
BCC = Z = 2 (in bcc structure the number of atoms are present is 2)
a = 500 = 500 X 10^-10 (to convert it into centimeter)
Na = 6.022 X 10^23
M = ?
d = Z M / a^3 Na
d a^3 Na / Z = M
7.5 X (500 X 10^-10)^3 X 6.022 X 10^23 / 2
45.165 X 125 X 10^6 X 10^23 X 10^-30 / 2
M= 282.281 g
Hope it will help you
BCC = Z = 2 (in bcc structure the number of atoms are present is 2)
a = 500 = 500 X 10^-10 (to convert it into centimeter)
Na = 6.022 X 10^23
M = ?
d = Z M / a^3 Na
d a^3 Na / Z = M
7.5 X (500 X 10^-10)^3 X 6.022 X 10^23 / 2
45.165 X 125 X 10^6 X 10^23 X 10^-30 / 2
M= 282.281 g
Hope it will help you
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