Chemistry, asked by Abhishekavarma5637, 1 year ago

An element crystallizes in a BCC lattice with cell edge of 500 picometre the density of element is 7.5 gram per centimetre cube how many atoms are present in 300 gram of the element

Answers

Answered by Rishukamboj
8
d = 7.5
BCC = Z = 2 (in bcc structure the number of atoms are present is 2)
a = 500 = 500 X 10^-10 (to convert it into centimeter)
Na = 6.022 X 10^23
M = ?


d = Z M / a^3 Na
 d a^3 Na / Z  =  M
7.5 X (500 X 10^-10)^3 X 6.022 X 10^23  / 2
45.165 X 125 X 10^6 X 10^23 X 10^-30 / 2
M=  282.281 g 
Hope it will help you



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