Physics, asked by AnuragNayak8868, 1 year ago

An element crystllizes in a


b.c.c. lattice with cell edge of 400 pm. calculate the density if 250 g of this element contain 2.5 x 1024 atoms?

Answers

Answered by DIVINEREALM
5
 here Z=2a=400×10^−10cm,a^3=64×10^24cm cube, mass of an atom= 250/25×10^23gmass of unit cell = no of atoms in the unit cell ×× mass of an atom=2×400/25×10^23g=32×10^−23gdensity = mass of unit cell / volume of unit cell=32×10^−23g/64×10^−24cmcube=50g/cmcube.
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