An element E forms a halide with formula EH4 which is a solid with low melting point. Element E is most likely to be in the same group of periodic table of Si. Identify element E
(Answer for 50 points but correct because I have boards)
Answers
Answer:
E is Carbon
Explanation:
carbon is the element which is solid with low melting point carbon also is most likely to be in the same group of periodic table of si so, an element if forms are there with the formula EH4 it is CH4 so the element is is carbon
Answer:
hey!
ANSWER
Covalent solids are soft, have a low melting point (due to relatively weak bonds), and are a poor conductor of electricity (due to absence of free ions).
white substance A reacts with dilute H
2
SO
4
to produce a colorless gas B and a colorless solution C. The reaction between B and acidified K
2
Cr
2
O
7
solution produces a green solution and a slightly colored precipitate D. This precipitate must be sulphur. So gas B must be hydrogen sulphide, and the white substance A must be some metal sulphide. Sulphur burns in air to produce sulphur dioxide (gas) which reacts with hydrogen sulphide to yield sulphur again and a colorless liquid water. Anhydrous copper sulphate is turned blue on an addition of water. The addition of aqueous NH
3
or NaOH to C produces, first, a precipitate which dissolves in excess of the respective reagent to produce a clear solution in each case. This suggests that C must be sulphate of either zinc or aluminum. So, A may be zinc sulphide.
ZnS+H
2
SO
4
⟶H
2
S+ZnSO
4
K
2
Cr
2
O
7
+4H
2
SO
4
⟶K
2
SO
4
+Cr
2
(SO
4
)
3
+4H
2
O+3[O]
[H
2
S+(O)⟶H
2
O+S]×3
------------------------------------------------------------------------------------------
K
2
Cr
2
O
7
+
4H
2
SO
4
+
3H
2
S
⟶
K
2
SO
4
+
Cr
2
(SO
4
)
3
Greensolution
+
7H
2
O
+
3S↓
S+O
2
⟶SO2
SO 2 +2H 2
S⟶2H2 O+3SZnSO
4+ 2NaOH 4⟶Zn(OH) 2
↓
White +Na 2 SO 4Zn(OH) 2 +2NaOH⟶Na2 ZnO 2 +2H 2aO