Question

an element E forms an oxide with formula E2O3.( a) state the valency of E (b)write the formula of its ÷(a)chloride (b) sulphate (c) phosphate​

Answer 1

Answer: (a) Valency of element E is  $+3$, (b) $ECl_{3}$ (c) $E_{2}(SO_{4})_{3}$ (d) $EPO_{4}$

Explanation:

(a) As the formula of a chemical compound is derived by the cross multiplication of the valency of the atoms. As formula of the given oxide is $E_{2} O_{3}$ and valency of O atom is $-2$; therefore valency of element E must be $+3$, in order to obtain $E_{2} O_{3}$.

(b) Formula of its Chloride is $ECl_{3}$. As valency of Cl is $-1$ and valency of element E is $+3.$

(c) Formula of its sulphate is $E_{2}(SO_{4})_{3}$. As valency of sulpate $(SO_{4}^{2-} )$ is $-2$  and valency of element E is $+3.$

(d) Formula of its phosphate is $EPO_{4}$. As valency of phosphate is $(PO_{4} ^{3-} )$ is $-3$ and valency of element E is $+3.$

#SPJ2

Answer 2

Explanation:

(a) The nature of oxide is basic as it turns red litmus paper blue.

(b) E is metal since it forms basic oxide.

(c) Sodium (Na) is one example of an element like E.

_____________________

_________________

____#_____

i hope u understand