An Element Forms An Oxide In Which The Oxygen Is 20 % of the oxide by mass, the equivalent mass of the element will be??
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1st method:
Let the total amount of oxide be 100
∴ mass of oxygen is 20
∴ mass of element is (100-20)=80
∴ equivalent mass of element=massofelementmassofoxygenmassofelementmassofoxygen×8×8
=8020=8020×8×8
=32
2nd method:
Equivalent mass of a metal is defined as the mass which combines with 8 gram of oxygen or 35.5 grams of chlorine or 1 gram of hydrogen.
Given: Mass of metal oxide = x = 100 g
mass of oxygen =
Thus mass of metal = Mass of metal Oxide - mass of oxygen = (100-20) g= 80 g
20 gram of oxygen combine with = 80 g of metal
So 8 gram of oxygen combines with = of metal
Thus equivalent mass of metal is 32 gram.
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