Question

An element found two oxides in one oxide of 1 gram of the side has 0.5 gram of the element in another oxide 4 gram of oxide has 0.8 gram of element so that it always law of multiple proportion ​

Answer 1

Answer:

let the two oxides of Cu be named A and B

oxide A

mass of Cu in 1g of oxide A = 0.888g  

mass of O in 1g of oxide A =1-0.888=0.112g

oxide B

mass of Cu in 1g of   oxide B = 0.799g

mass of O in g of oxide B = 1-0.799=0.201g

In oxide A , 1g Cu is combined with oxygen = 0.112 x 1/0.888 = 0.126g

In oxide B , 1g Cu is combined with oxygen = 0.201 x 1/0.799 = 0.252g

the different weight of oxygen combined with a fixed weight (1g) of Cu are in ratio 0.126 : 0.252  or 1: 2

This is a simple whole ratio that shows the agree with the law of multiple properties .