An element has a body centred cubic (bcc) structure with a cell edge of 444 pm. The density of the element is 7.2 g/cm. How many atoms are present in 404g of the element? (A) 3.12 x 1024 unit cells (B) 9.24 x 1024 unit cells (C) 6.41x1023 unit cells (D) 12.08 x 1023 unit cells
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Answer:
C
Volume of the unit cell =\left ( 444\times 10^{-10} \right )^{3}
wherein
Where,
d = density of crystal
z = no. of effective constituent particles in one unit cell
M = molecular weight
a = edge length of unit cell
No = 6.022*1023 so it is c
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