Question

An element has a body-centred cubic structure with a cell edge of 4 x 10-8 cm. Calculate diameter of an particle.​

Answer 1

Explanation:

Edge length ‘a’ = 288 pm = 288 x 10-10 cm Density (d) = 7.2 g cm-3, Mass of element = 208 g = 51.8 g mol-1 According to mol concept 51.8 g element has = 6.022 x 1023atoms ∴208 g of element will have = 208 51.8 × 6.022 20851.8×6.022 x 1023 atoms = 24.17 x 1023 atomsRead more on Sarthaks.com - https://www.sarthaks.com/689689/an-element-has-a-body-centred-cubic-bcc-structure-with-cell-edge-of-288-pm

Answer 2

Answer:

0.865×10^-8

Explanation:

r=√3a/4

diameter =√3a/8

d=1.73×4×10^-8/8

d=0.865×10^-8