Question

An element has an electronic configuration of (2 8 8 2) .If it has one neutron more than the number of protons it has then find its (i) atomic number (ii) mass number​

Answer 1

Answer:

i) 20

ii) 41

explanation:

i)At. no is 20(2+8+8+2)

ii) Since given that the atom has one neutron more than the no. of proton

At. no = Proton no.

So, proton no. = 20

Thus, neutron no. = 20+1 = 21

Therefore, Mass no. = Proton no. + Neutron no.

= 20 + 21

= 41

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