Question

An element has atomic number 30, it contains 2 units positive charge, how many protons and electrons present ?

Answer 1

Answer:

Explanation:

Atomic number=number of protons=30

Since cation has 2 units positive charge(two electrons removed)

no. of electrons=30−2=28

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Answer 2

Answer:

No.of protons = 30

No. of electrons = 28

Explanation:

Z = Atomic no. = 30

units of positive charge = 2

atomic no. = no. of protons = p = 30

Since, no. of protons = units of charge + no. of electrons

30 = 2 + e

e = 28

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