Question

An element has bcc structure with all.Edge 288pm the density of element 7.2gcm^3 how many atoms are present in 207g of the element

Answer 1

Density= (atom in a unit cell × molar mass)/ Avogadro's no× edge length^3)

density= Z×M/ Nà×a^3

In bcc z= 2

We can easily find molar mass from here

Then no of moles= 207/molar mass

No of atom= no of moles × Avogadro's no