Question

An element has four isotopes, each differing by an atomic mass of 1. The ratio of their abundance from the lightest to heaviest isotope is 1:2:2:3, respectively. Determine the average atomic mass of the element, if the mass of the heaviest isotope is A.​

Answer 1

Answer:

8A-9

Explanation:

MASS OF HEAVIEST=A

mass of 1st istope =A-3

MASS OF 2ND ISOTOPE=A-2

MASS OF 3RD ISOTOPE=A-1

RATIO OF NATURAL ABUNDANCE=1:2:2:3

A.V.G MASS =A*3+(A-1)*2+(A-2)*2+(A-3)*1=8A-9

Answer 2

Answer:

8A -9 is the right answer