Question

An element has two isotopes of masses 83 and 87 and average atomic mass is 84.6.Find the ratio of their natural abundance.​

Answer 1

Given info : An element has two isotopes of masses 83 and 87 and average atomic mass is 84.6.

To find : The ratio of their natural abundance is...

solution : let the ratio of their natural abundance is m : n.

average atomic mass = (m × mass of 1st isotope + n × mass of 2nd isotope)/(m + n)

here average atomic mass = 84.6

mass of 1st isotope = 83

mass of 2nd isotope = 87

∴ 84.6 = (m × 83 + n × 87)/(m + n)

⇒84.6(m + n) = (83m + 87n)

⇒84.6m + 84.6n = 83m + 87n

⇒1.6m = 2.4n

⇒2m = 3n

⇒m/n = 3/2

Therefore the ratio of their natural abundance is 3 : 2.

Answer 2

Answer:

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