Question

• An element having atomic number 37 is : (i) An active metal (ii) A transition metal (ii) A halogen (iv) An inert gas​

Answer 1

Answer:

The atomic number is 37.

2+8+8+18+1=37

Thus the last shell will have one electron.

Hence, the group number is 1 or IA.

It is an alkali metal.

Explanation:

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Answer 2

• The correct option is  (i) An active metal.

• We know that the Rubidium has atomic number 37. The rubidium reacts quickly or strongly with other substances, so it is known as an active metal.

• Rubidium denoted by Rb. is a soft alkali metal.
• The activity of the rubidium metal at the bottom will be the most active. it belongs to group 1.

• So that the element having atomic number 37 is an active metal i.e Rubidium.