Question

An element having bcc structure has unit cell edge 400pm. Then density of element is

Answer 1

Answer:

Explanation:Given, M = 100 g/mol, a = 400pm  

For BCC -  

n=8×  

8

1

​  

+1=2

As we know,

Density=  

a  

3

×N  

A

​  

 

n×M

​  

 =  

(400×10  

−10

)  

3

×6.02×10  

23

 

2×100

​  

 =5.188 g cm  

−3

 

(∵400pm=400×10  

−10

cm)