Question

An element having which of the following electronic configurations would have the greatest ionization energy?

A) [He] 2s22p3
B) [He] 2s22p5
C) [Ne] 3s23p3
D) [Ne] 3s23p5

Answer 1

Answer:

option A is correct.

Explanation:

because in He atom 2p3 electron are more closer to nucleus so more energy is required to remove electron in 2p3 p orbital as compare to other.

Answer 2

Answer: Option B

Explanation:

As my teacher explained to me Fluorine is the sexiest of all elements and attracts the most ions. This is because it's so small and closer to the nucleus that it would have the greatest ionization energy.