Question

An element is found in nature in two isotopic forms with atomic number (A-1) and (A-3). If the average atomic mass is found to be A, then find the relative abundance of the heavier isotope.​

Answer 1

Answer:

The solution is laid out like this:

(exact weight of isotope #1) (abundance of isotope #1) + (exact weight of isotope #2) (abundance of isotope #2) = average atomic weight of the element

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Answer 2

Answer:

take the abundance of (a-1)as X and abundance of (a+3)as (100-x)