An element is placed in 2nd group and 3rd period of the periodic table, burns in the presence of oxygen to form a basic oxide. I) identify the element ii) write the electronic configuration
Answers
Answered by
1
The element is Magnesium E. C is 1s2 2s2 2p6 3s2
Answered by
2
3 period means it has 3 orbitals.
2 group mean it has 2 electron in its last orbit but it is not applicable for all but from group 1-2 & 13-18 it is. as for boron electronic configration is 2,3 as last orbit has 3 electron so add 10 you will get group and to find period count otbital it has 2 orbital so period is 2.
AND IN YOUR CASE
.3 ORBITAL
.2 ELECTRON IN LAST ORBIT SO
ITS ELECTRONIC CONFIGURATION IS
2,8,2
ATOMIC NO=12
ELEMENT=Mg
hope this help you
2 group mean it has 2 electron in its last orbit but it is not applicable for all but from group 1-2 & 13-18 it is. as for boron electronic configration is 2,3 as last orbit has 3 electron so add 10 you will get group and to find period count otbital it has 2 orbital so period is 2.
AND IN YOUR CASE
.3 ORBITAL
.2 ELECTRON IN LAST ORBIT SO
ITS ELECTRONIC CONFIGURATION IS
2,8,2
ATOMIC NO=12
ELEMENT=Mg
hope this help you
Similar questions