An element m is present in 3rd a group of periodic table write formula of its chloride and oxide
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21
as the element belongs to 13th group so it will have 3 electrons in its outermost shell. it needs 5 more electrons to complete its octet and so it requires a lot of energy to gain electrons so it will loose 3 electrons.
clorine has electronic configurqtion as 2,8,7. it needs to gain 1 electron.
now let the element be X
formula therefore becomes,
X Cl
3 ↗↖ 1
XCl3
formula of oxides=
X O
3 ↗↖ 2
X2O3
hope it helps you.
please mark it as brainliest.
clorine has electronic configurqtion as 2,8,7. it needs to gain 1 electron.
now let the element be X
formula therefore becomes,
X Cl
3 ↗↖ 1
XCl3
formula of oxides=
X O
3 ↗↖ 2
X2O3
hope it helps you.
please mark it as brainliest.
Answered by
5
Answer:
The oxide will be in the form of R2O2 and chloride will be in the form of RCL3
Explanation:
According to the Mendeleev's periodic table's formula of oxides and hydrides.
And we can also calculate the formula oxides and hydrides by their valencies too.
X. O
3. 2
Ans: X2O3.
X. Cl
3. 1
Ans: XCl3.
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