Question

An element occurs in two isotopic from with atomic masses 10and11 what is the percentage of abundance of two isotops in the simple having atomic masses 10.80

Answer 1

The percent abundance can be calculated by using the formula:

Average atomic weight of the element =  (exact weight of isotope 1) X (abundance of isotope 1) + (exact weight of isotope 2) X (abundance of isotope 2)

Let the abundance of B-10 be assigned 'x' and the B-11 be '1 - x.'

So, (x) (10) + (1 - x) (11) = 10.8

10x + 11 - 11x = 10.8

x = 0.2

1 - x = 0.8

So, the percent abundance of B-10 is 20% and of B-11 is 80%.

MARK BRAINLIEST

Answer 2

The percent abundance can be calculated by using the formula:

Average atomic weight of the element = (exact weight of isotope 1) X (abundance of isotope 1) + (exact weight of isotope 2) X (abundance of isotope 2)

Let the abundance of B-10 be assigned 'x' and the B-11 be '1 - x.'

So, (x) (10) + (1 - x) (11) = 10.8

10x + 11 - 11x = 10.8

x = 0.2

1 - x = 0.8

So, the percent abundance of B-10 is 20% and of B-11 is 80%.

MARK BRAINLIEST