Question

an element P shows two valencies 3 and 4. Write the formula of possible oxides of this elements.​

Answer 1

Answer:

one is P2O3 and another one will be PO2

Explanation:

As element P is having 3 and 4 valency

As it reacts with Oxygen with valency 2 forms P2O3

when it react with oxygen with valency 4 it forms PO2

Answer 2

The formula of possible oxides of this elements are $P_2O_3$ and $PO_2$​

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Here element P is having an oxidation state of +3 called as $P^{3+}$ cation and $O^{2-}$ is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $P_2O_3$

Here element P is having an oxidation state of +4 called as $P^{4+}$ cation and $O^{2-}$ is an anion with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $PO_2$

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