Question

An element posses close cubic packing struscture.calculate the radius of the atom in unit cell.(a=252 nm)​

Answer 1

Answer:

Explanation:

In cubic closed pack structure, the face diagonal of the cube is  

4 × r  where  r  is the radius of the atom  Face Diagonal of CCP=

√ 2 × a  thus,  √ 2 × a = 4 × r √ 2 × 252 =4×r

r=89.1 nm .

Answer 2

Answer: 89.36nm

Explanation:

In cubic closed pack structure, the face diagonal of the cube is  

4*r  

where  

r = is the radius of the atom

Face Diagonal of CCP=

√ 2*a thus,  

√ 2*a=4*r  √2*252=4*r  

89.1nm

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