an element shows variable valencies 4 and 6. write the formulae of its oxide
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heya
The valency of Oxygen is -2.
So when B shows the valence as 4 the formula formed is BO2. And when B shows the valence as 6 the formula formed is BO3.
Hence, when an element B shows valence numbers of 4 and 6, the formulae of its two oxides is BO2 and BO3
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Answered by
1
Let the element = X
i) XO2
ii) XO3
i) XO2
ii) XO3
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