Chemistry, asked by sanikab396, 6 months ago

An element with density 2.8g/cm³ forms a fcc unit cell edge length 4×10^-8

Answers

Answered by sunkerkaranushree
2

Answer: Molar mass is 27g mol^-1

Explanation:

Density (D) = 2.8g cm^-3

Unit cell f.c.c.(Z) = 4

Edge length (a) = 4✖️10^-8 cm

Avogadro’s number (NA) = 6.022✖️10^23 mol^-1

Molar mass (M) = ?

=> D = Z✖️M / NA ✖️ a^3

=> M = D✖️a^3✖️NA / Z

= 2.8g cm^-3(4✖️10^-8cm)^3✖️6.022✖️10^23 / 4

= 2.8✖️16✖️10^-1✖️6.022

.*. M = 26.98g mol^-1

= 27g mol^-1

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