an element with density with 11.2gpercm^3 form A FCC lattice with edge length og 4×10^-8cm. calculate the atomic mass of the Element.explain
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Explanation:
density , d = 11.2g cm^3
edgelength a = 4×10^-8cm.
Avagedro number , NA = 6.022 * 10^23
Number of atoms present per unit cell ,Z(FCC) = 4
We know for crystal system
d=z*m/a^3*Na
m=d*a^3*Na/Z
We get,
M = 11.2*64*10^-4*6.022 * 10^23/4=107.91g
This the atomic mass of the element is 107.91g
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