An element with mass number 81 contains 31.7 percentage more neutrons and protons. Give the atomic number of the element...
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3
A(atomic mass)=no of protons+no of neutrons
given that neutrons are 31.7%more than neutrons
ie..,,
% of neutrons = % of protons+ 31.7%
=x(say)+31.7%
but % of protons+ neutrons= 100
x+x+31.7=100
2x=68.3
x=34.15% =34.15% of 81
=34.15÷100*81~=28
given that neutrons are 31.7%more than neutrons
ie..,,
% of neutrons = % of protons+ 31.7%
=x(say)+31.7%
but % of protons+ neutrons= 100
x+x+31.7=100
2x=68.3
x=34.15% =34.15% of 81
=34.15÷100*81~=28
Answered by
0
Answer:
We know that mass number of the element,
A = p+n = 81
Let the number of protons, p = x
Then, number of neutrons,
n= x+ 31.7 / 100x = 1.317 x
(As number of neutrons are 31.7% more than the protons.) Hence, from Eq. (i)
x + 1.317 x = 81
x = 81 / 2.317 = 34.958 = 35 (approx)
Therefore, number of protons = 35 and the symbol is ${}_{35}^{81}Br$ (Number of protons = Atomic number)
Explanation:
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