Question

An element X (at. no.11)combines with an element Y (at.no.17).
a. Identify the nature of the bond between X and Y.
b. Show the formation of bond between X and Y using electron dot structure.
c. List 4 properties exhibited by this compound. ​

Answer 1

Answer:

a)NaCL

nature of bond = ionic bond

c)

Sodium chloride, a white crystalline solid, contains a density of 2.165 g/mL, the melting point of 801 °C, and the boiling point is about 1,413 °C. It is also available as aqueous solutions with different concentrations, which are known as saline solutions

Answer 2

CHEMICAL BONDING -

• The element with atomic number 11 will have electronic configuration 2,8,1 so will lie in s-block and group1 in the periodic table.
• The element is sodium placed in period 3 of the table.
• The element with atomic number 17 is chlorine having an electronic structure 2,8,7.
• Chlorine is present in the 17th group and the 3rd period in the periodic table.
• When sodium forms a bond with chlorine, an ionic compound of sodium chloride (NaCl) is formed.

(a) The bond present between the elements Na and Cl is an Ionic bond.

• The sodium atom loses one electron and chlorine has the affinity to accept one electron to form a bond.
• A Sodium cation is formed whereas chlorine forms an anion.

(b) The bond formed between the elements can be represented by an electron dot structure.

• The diagram shows the electron transfer and the stability attained by both the atoms by the formation of the bond.

(c) Properties of sodium chloride -

• Soluble in water and other solvents.
• Odourless compound but have some taste.
• The aqueous solution, is a good conductor of electricity.
• Decomposes at high-temperature forming disodium oxide and hydrochloric acid.