Question

An element X crystallizes in fcc structure, 208g of this element have 4.283*10**24 atoms. Calculate edge length of the unit cell, if the density of X is 7.2gcm**-3

Answer 1

Explanation:

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Answer 2

Answer:3x10^-8

Explanation:

Volume of the unit cell = a^3

∴ Mass of the unit  cell = (4 x 208)/(4.283 x 10^24)

                                   ≈194 x 10^-24g

Density = Mass/Volume

     7.2 = (194 x 10^-24)/a^3

∴a^3 =  (194 x 10^-24)/7.2

 a^3=27 x 10^-24

 a=∛(27 x 10^-24)

 a=3 x 10^-8

∴ Edge of the unit cell = 3 x 10^-8cm

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