Question

An element x forms an Oxide of molecular formula X2O3. THE percentage of the element X in it is 53. Find the atomic mass of the element

Answer 1

Answer:

27.06

Explanation:

let atomi mass of the element =x

molar mass of the compound= 2x +48

$\frac{mass \: of \: element}{molar \:mass \: of \: the \: compound \: } = mass\% \\ \frac{2x}{2x \ + 48} \times 100 = 53 \\ x = 27.06$

Answer 2

Answer:

let atomic mass of the element =x

molar mass of the compound= 2x +48

\begin{lgathered}\frac{mass \: of \: element}{molar \:mass \: of \: the \: compound \: } = mass\% \\ \frac{2x}{2x \ + 48} \times 100 = 53 \\ x = 27.06\end{lgathered}molarmassofthecompoundmassofelement=mass%2x +482x×100=53x=27.06

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