An element x forms two oxides, formula of first oxide is xo2.The first oxide contains 50% of oxygen.If the second oxide contains 60% oxygen ,the formula of the second oxid
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Given:
An element x forms two oxides, the formula of the first oxide is xo2. The first oxide contains 50% of oxygen.
To find:
If the second oxide contains 60% oxygen, the formula of the second oxide is?
Solution:
From given, we have,
The formula of the first oxide is xo2.
The first oxide contains 50% of oxygen.
32/32+x = 50% = 50/100
32/32+x = 0.5
The molecular weight of the metal, x=32
The second oxide contains 60% oxygen.
16n/32+16n = 60% = 60/100
16n/32+16n = 0.6
upon solving, we get,
n = 3
Therefore, the formula of the second oxide is YO3
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