Question

An element X has an electronic configuration of 2, 8, 3 . What type of bonding and compound will it form ?​

Answer 1

Answer:

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Ionic bond.

More information:-

⏩ The ionic bond is also called electrovalent bond . This bond is formed generally due to the transfer of electrons .

⏩ Covalent bonds are formed due to the sharing of electrons but ionic bonds are formed due to electron transfer .

⏩ The ionic bond is a chemical bond formed between electropositve metals and electronegative non metals .

⏩ In the given case X has an electronic configuration of 2 , 8 , 8 , 1 which means that it contains 1 valence outermost electron .

⏩ Y has an electronic configuration of 2 , 8 , 7 which means that it contains 7 outermost electrons .

⏩ We know that an atom tends to attain stable electronic configuration to its nearest noble gas . Here the element X needs to donate 1 electron to complete its octet .

⏩ On the other hand , the element Y requires to accept 1 electron so as to complete its octet ,

⏩ Thus there will be transfer of electrons from X to Y .

⏩ After the transfer X will turn into a positive univalent ion with a deficit of one electron .

⏩ Y will turn into a negative univalent ion with an excess of one electron .

⏩ The bond will be ionic bond as there is transfer of electrons in this case .

Hope it helps!

Answer 2

Answer:

Explanation:

IONIC BOND

as its outermost orbit has 3 electrons so it will lose a electron

and losing electrons led to formation of IONIC BOND