Question

An element x has atomic mass 27 and atomic number 13 draw the atomic structure of an atom x when it loses 3 eltrons

Answer 1

$\huge\mathbb{\blue{QUESTION-}}$

An element x has atomic mass 27 and atomic number 13 draw the atomic structure of an atom x when it loses 3 electron.

$\huge\mathbb{\blue{SOLUTION-}}$

$\large\underline{\underline{\sf Given:}}$

• Atomic mass of x = 27
• Atomic number of x = 13

i.e element is $\sf{ Al_{13}^{27}}$

• Element loses 3 electron.

$\large\underline{\underline{\sf To\:Find:}}$

• Atomic structure of new element.

Now ,

Al electronic configuration is

1s² 2s² $\sf{2p^6}$ 3s² 3p¹

After losing three electrons it's configuration changes to -

1s² 2s² $\sf{2p^6}$ .

⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯

Refer to the Attachment for the atomic structure of the element.