An element "x" has mass no 35 and the no of newtron is 18 . Identify the group no and period of "x"
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Answered by
3
Given, Mass Number = 35
Number of neutrons = 18
Number of electrons = 35 - 18 = 17 .
So, The Atomic Number of the element is 17 .
The element is Chlorine.
Group number VIIA ( 7 A) or 17 ( Halogens)
Period number 3
Number of neutrons = 18
Number of electrons = 35 - 18 = 17 .
So, The Atomic Number of the element is 17 .
The element is Chlorine.
Group number VIIA ( 7 A) or 17 ( Halogens)
Period number 3
Answered by
3
mass number = 35
number of neutron = 18
as we know
Mass number = number of protons + number of neutrons.
let number of protons = x
so
35=× +18
×=35 - 18
X=17.
as we know
number of protons in a atom = number of electrons in a atom
17 = number of electrons
hence element is chlorine as chlorine has atomic number 17
electronic configuration
k shell = 2
l shell = 8
m shell = 7
so valency = 1
and period is 3
number of neutron = 18
as we know
Mass number = number of protons + number of neutrons.
let number of protons = x
so
35=× +18
×=35 - 18
X=17.
as we know
number of protons in a atom = number of electrons in a atom
17 = number of electrons
hence element is chlorine as chlorine has atomic number 17
electronic configuration
k shell = 2
l shell = 8
m shell = 7
so valency = 1
and period is 3
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