An element x has mass number 35 and number of neoutrons is 18identify the group no.and period of x
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No of protons= mass no - no of neutrons
= 35-18 = 17
no of protons= atomic no
therefore atomic no=17
electronic configuration= 2,8,7
Group no= 17
period= 3
= 35-18 = 17
no of protons= atomic no
therefore atomic no=17
electronic configuration= 2,8,7
Group no= 17
period= 3
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