An element x has mass number 35 and the number of neutron is 18 identify the number of group number and periodic of x
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1
So mass of the given element = 35
no. of given neutron = 18
mass no. of an element = no. of proton + no. of neutron
Therefore,
35 = no. of proton + 18
no. of proton = 35-18 = 17
no. of proton = atomic no. of that element.
and the element with atomic no. as 17 is chlorine.
Hence your answer is Chlorine.
Hence it's period is 3 and Group is VIIA(17).
no. of given neutron = 18
mass no. of an element = no. of proton + no. of neutron
Therefore,
35 = no. of proton + 18
no. of proton = 35-18 = 17
no. of proton = atomic no. of that element.
and the element with atomic no. as 17 is chlorine.
Hence your answer is Chlorine.
Hence it's period is 3 and Group is VIIA(17).
Answered by
0
Answer:
We know :
Atomic number = Mass number - No. of neutrons.
Atomic number = 35 - 18
= > 17
Electronic configuration :
2 , 8 , 7
Group no. = 17
Period no. = 3
Name of element is Chlorine ( Cl ) .
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