An element X has Mass Number (A)= 23 and have 12 neutrons in its nuleus. What will be its electronic configuration?
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Explanation:
Mass no. = no. of protons + no. of neutrons
23 = no. of protons + 12
∴ no. of protons = 23−12
=11
Atomic number (Z) = no. of protons = no. of electrons =11
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