Question

An element ‘X’ has same number of electrons in the first and the fourth shell as well as in the second and the third shell.

i) Write down the electronic configuration of the element.

ii) Write down the group number and the period to which it belongs.

iii) What is the valency of the element?

iv) State whether the given element is a metal or a non-metal? How the metallic character of elements varies in a group and why?

Answer 1

An element "X = Calcium" have same number of electrons in the first (K shell) and the fourth shell (N shell) as well as in the second (L shell) and the third shell (M shell).

$Calcium \: with \: Atomic \: no. \: 20.$

(i) Electronic configuration:-

${1s}^{2} \: {2s}^{2} \: {2p}^{6} \: {3s}^{2} \: {3p}^{6} \: {4s}^{2}$

Electron distribution = (2,8,8,2) → (K,L,M,N).

(ii) 2nd group and 4th period.

(iii) The Valency of Calcium is +2.

(iv) The given element (Calcium) is metal. Metallic character decreases across the period and decreases down the group. Left side of the periodic table consist Metals and Right side of the periodic table consist Non-metals.

Answer 2

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Explanation: An element "X = Calcium" have same number of electrons in the first (K shell) and the fourth shell (N shell) as well as in the second (L shell) and the third shell (M shell).

Calcium \: with \: Atomic \: no. \: 20.CalciumwithAtomicno.20.

(i) Electronic configuration:-

2,8,8,2

(ii) 2nd group and 4th period.

(iii) The Valency of Calcium is +2.

(iv) The given element (Calcium) is metal. Metallic character decreases across the period and decreases down the group. Left side of the periodic table consist Metals and Right side of the periodic table consist Non-metals.