Question

An element X has the following isotopic composition,
200 X : 90% . 199 X: 8.0% , 202 X : 2.0%.
The weighted average atomic mass of the naturally
occurring element X is closest to:
​

Answer 1

Answer:

average atomic mass

=200*90+199*8+202*2/100

=19996/100

=199.96

average atomic mass is nearly equals to 200 amu

Answer 2

Answer:

The weighted Average atomic mass of element [x]

=0.9(200)+0.08(199)+0.02(202)

=180+15.92+4.04

=199.96amu

≈200 amu

The weighted average atomic mass of the naturally occurring element X is closest to 200 amu

hope it helps you...