an element X have 3 isotpes X20,X21,X22. the percentage abundance of X20 is 90% and it's average atomic mass of the element is 20.11 the percentage abundance of X21 should be:
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it will be 9%.
20*0.90+0.21(x)+0.22(10-x)=20.11 ....by solving this x will be 9%...
20*0.90+0.21(x)+0.22(10-x)=20.11 ....by solving this x will be 9%...
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