an element x is atomic number 3, relative atomic mass 6.94 and consist of two isotopes of mass number 6 and 7 respectively .calculate the relative abundance of each isotope
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It’s a simple 2 variable algebra problem. I will solve with the substitution method.
6x + 7y = 6.94
x + y = 1
Therefore
x + y = 1
x + y – x = 1 – x
y = 1 – x
Substitute y for (1 – x)
6x + 7(1 – x) = 6.94
6x +7 – 7x = 6.94
7 – x = 6.94
7 – x – 7 = 6.94 – 7
–x = –0.06
x = 0.06
So 6% mass 6. The remaining 94% would be mass 7.
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