An element X, which is radioactive and has half life tv2= 20 days. The daughter nuclei formedafter decay of X is 2-6 Y. Calculate the volume of He collected at S.T.P after 40 days if 2 mole ofX is placed in a sealed tube
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Answer:
The answer is 100.8 lit
Explanation:
X (parent nuclei) ------>. Y (Daughter nuclei) + 3He
Daughter nuclide whose atomic number is 6 less and atomic mass is 12 less than the original element.
t =0 2 mole 0 mole 0 mole t(1/2) = 20 days
t (1/2) 1 mole 1 mole 3 mole 2t(1/2) = 40 days
t=2t(1/2) 1/2 mole (1+1/2) mole (3 +3/2) mole
Mole of He after 2 half-life = 4.5 mole
The volume of 4.5 moles of He at STP = 4.5 x 22.4 = 100.8 lit
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