an element xhas the following isotopic composition 200x=90% 199x=8%and 202x2%the weight average atomic Mass of the element xis closed to
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90%-200
8%-199
2%-202
MASS OF THE ELEMENT IN THE ATMOSPHERE=(200×90+8×199+2×202)÷100=200amu
8%-199
2%-202
MASS OF THE ELEMENT IN THE ATMOSPHERE=(200×90+8×199+2×202)÷100=200amu
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