An element ZSA decays to 85R222 after emitting 2 a particles and 1 B particle. Find the
atomic number and atomic mass of the element S.
Answers
Answered by
13
Answer:
ANSWER
On emission of 2 alpha particles, mass number is reduced by 8 and atomic number by 4.
z
S
A
→
z−4
Q
A−8
+2
2
He
4
Now, on emission of 1 beta particle, mass number remains same but atomic number increases by 1.
z−4
Q
A−8
→
z−8
R
A−8
+
−1
0
β
After decay, given element is
85
R
222
.
Therefore,
A−8=222⇒A=230
(Atomic Mass)
Z−3=85⇒Z=88
(Atomic Number)
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Answered by
2
Answer:
85 is your answer.........
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