Question

An element ZSA decays to 85R222 after emitting 2 a particles and 1 B particle. Find the
atomic number and atomic mass of the element S.​

Answer 1

Answer:

ANSWER

On emission of 2 alpha particles, mass number is reduced by 8 and atomic number by 4.

z

S

A

→

z−4

Q

A−8

+2

2

He

4

Now, on emission of 1 beta particle, mass number remains same but atomic number increases by 1.

z−4

Q

A−8

→

z−8

R

A−8

+

−1

0

β

After decay, given element is

85

R

222

.

Therefore,

A−8=222⇒A=230

(Atomic Mass)

Z−3=85⇒Z=88

(Atomic Number)

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Answer 2

Answer:

85 is your answer.........