An elephant of length 4m is at one corner of a rectangular cage 16m × 30m and facing towards the diagonally opposite corner. If the elephant starts moving towards the diagonally
opposite corner it takes 15 seconds to reach the opposite corner. Find the speed of the
elephant (in m/s).
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Answered by
1
Answer:
Answer:
we have to find the diagonal first
diagonal of rectangle =
\sqrt{ {l }^{2} + b}^{2} }
=
\sqrt{ { \binom}{ 30m }^{2} + { \binom{16m}^{2} }
=
\sqrt{900m}^{2} + 256m}^{2} }
=
\sqrt{1156}
1156
=34m
distance to be cover by the elephant
=34m-4m
=30m
speed=distance
time
=30m
15sec
=2m/sec
Answered by
0
Explanation:
AC=AB2+BC2−−−−−−−−−√=302+162−−−−−−−−√
=900+256−−−−−−−−√
=1156−−−−√=34metre.
Distance travelled by elephant = 34 - 4 = 30 metre
speed of elephant =3015
=2m/s
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