Question

An elephant of length 4m is at one corner of rectangular cage of size 16m *30m and faces towards diagonally opposite corner if elephant starts moving towards diagonally opposite corner it takes 15 seconds to reach this corner .find speed of elephant

Answer 1

Diagonal length = 34m, distance covered 34-4=30m. Speed is 30/15 m/s = 2m/s

Answer 2

Answer:

we have to find the diagonal first

diagonal of rectangle =

$\sqrt{ {l }^{2} + b}^{2} }$

=

$\sqrt{ { \binom}{ 30m }^{2} + { \binom{16m}^{2} }$

=

$\sqrt{900m}^{2} + 256m}^{2} }$

=

$\sqrt{1156}$

=34m

distance to be cover by the elephant

=34m-4m

=30m

speed=distance

time

=30m

15sec

=2m/sec

Hope it helps you

thanks