Question

. An elephant stand by its 4(four) legs and cover area of 2.5 m2. The mass of an Elephant is 350 kg and it is stand only by its own 3 legs, what would be the pressure exerted by an elephant?
Full

Answer 1

Explanation:

area covered by 1 leg = 2.5÷4

0.625m^2

area covered by 3 legs = 0.625×3

= 1.875m^2

pressure = force / area

250× 9.8/ 1.875= 1306.6 pa

Answer 2

Answer:

the pressure exrted by the elephant=186.66kgfm2

Explanation:

• area covered by 4 legs of the elephant =2.5m2
• so,area covered by 3legs: 2.5/4*3(unitary method)=1.875
• mass of elephant=350kg
• so weight of the elephant=350kgf
• as pressure exerted=force (weight of the elephant)/area (area covered by the elephant by 3 legs)
• therefore,pressure exerted by the elephant=350/1.875=186.66kgfm2(answer)
• HOPE IT HELPS!!!