Math, asked by parthdube447, 3 months ago

An elephant weighs 40,000n each of its four feet an area of 500cm2. If elephant stands on one foot what pressure does it put on the ground​

Answers

Answered by gongalladithya
2

Answer:

Step-by-step explanation:

ANSWER

Weight of elephant=40000N  

Area of one foot  = 1000 cm  

2

=1000×10  

−4

m  

2

 

Weight of girl=400N

Area of heel of girl  = 1 cm  

2

=1×10  

−4

m  

2

 

(a) Elephant has a larger weight of 40000N, therefore, elephant exerts a larger force on the ground. Elephant exerts a larger force on the ground by 40000N  - 400 N = 39600 N.

(b) Weight of elephant = 40000N

Area of one foot = 1000 cm  

2

=1000×10  

−4

m  

2

 

Pressure=  

Area

Force

​  

 

Pressure=  

1000×10  

−4

 

40000

​  

=400000N/m  

2

 

(c) Weight of the girl = 400N

Area of heel of girl =1 cm  

2

=1×10  

−4

m  

2

 

Pressure=  

Area

Force

​  

 

Pressure=  

1×10  

−4

 

400

​  

=4000000N/m  

2

 

(d) Girl exerts a larger pressure on the ground.

(e) Ratio =  

Pressure exerted by the elephant

Pressure exerted by the girl

​  

=  

400000

4000000

​  

=  

1

10

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