Physics, asked by lostduck247, 6 months ago

An elephant weighs 40000N. Each of its feet has an area of 0.08m^2. When standing on all four feet, what pressure does the elephant exert on the ground?

Answers

Answered by jagrativanya1812
1

Answer:

1.25 × 10^5 Pa

Explanation:

Pressure = Force / Area

Force given = 40000N.

Area = .08m^2 × 4 ( for 4 feet)

Pressure = 40000 / 0.32

= 125000 = 1.25 × 10^5 Pa

Answered by SoumyadeepNath
0

Answer:

Hey there here is your answer!

Force=4000N

Area of each foot=0.08m^2

Therefore, pressure=force×area

therefore, pressure on each foot=(400×0.08^2)Pa

=320 Pa

therefore, pressure on all four feet=

(320×4)Pa

=1280Pa

Please mark brainliest

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